Leetcode - 615. Average Salary: Departments VS Company
문제
정답
temp 테이블을 하나 만들고, 여기서 구한 평균을 이용해 CASE
문을 사용했다.
SELECT Salary.pay_month, department_id,
CASE
WHEN amount > average_amount THEN "higher"
WHEN amount = average_amount THEN "same"
ELSE "lower"
END AS comparison
FROM (
SELECT DATE_FORMAT(pay_date, '%Y-%m') AS pay_month, AVG(amount) AS amount, department_id
FROM Salary
JOIN Employee ON Salary.employee_id = Employee.employee_id
GROUP BY department_id, pay_month
) AS Salary
JOIN (
SELECT DATE_FORMAT(pay_date, '%Y-%m') AS pay_month, AVG(amount) as average_amount
FROM Salary
GROUP BY pay_month
) AS Monthly ON Salary.pay_month = Monthly.pay_month