Leetcode - 328. Odd Even Linked List

문제

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정답

홀수와 짝수 인덱스의 링크드 리스트를 따로 진행시키면 됩니다.

class Solution:
    def oddEvenList(self, head: Optional[ListNode]) -> Optional[ListNode]:
        if head is None:
            return head

        odd = head
        even_head = even = head.next
        while odd.next and even.next:
            odd.next = odd.next.next
            even.next = even.next.next

            odd = odd.next
            even = even.next

        odd.next = even_head

        return head